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如何使用python制作贪吃蛇大冒险

发表于:2025-02-08 作者:千家信息网编辑
千家信息网最后更新 2025年02月08日,如何使用python制作贪吃蛇大冒险,很多新手对此不是很清楚,为了帮助大家解决这个难题,下面小编将为大家详细讲解,有这方面需求的人可以来学习下,希望你能有所收获。导语贪吃蛇,大家应该都玩过。当初第一次
千家信息网最后更新 2025年02月08日如何使用python制作贪吃蛇大冒险

如何使用python制作贪吃蛇大冒险,很多新手对此不是很清楚,为了帮助大家解决这个难题,下面小编将为大家详细讲解,有这方面需求的人可以来学习下,希望你能有所收获。

导语

贪吃蛇,大家应该都玩过。当初第一次接触贪吃蛇的时候 ,还是我爸的数字手机,考试成绩比较好,就会得到一些小奖励,玩手机游戏肯定也在其中首位,毕竟小孩子天性都喜欢~

当时都能玩的不亦乐乎。今天,我们用Python编程一个贪吃蛇游戏哦~

正文

1.将使用两个主要的类(蛇和立方体)。

#Snake Tutorial Python import mathimport randomimport pygameimport tkinter as tkfrom tkinter import messagebox class cube(object):    rows = 20    w = 500    def __init__(self,start,dirnx=1,dirny=0,color=(255,0,0)):        pass            def move(self, dirnx, dirny):        pass        def draw(self, surface, eyes=False):        pass         class snake(object):    def __init__(self, color, pos):        pass     def move(self):        pass             def reset(self, pos):        pass     def addCube(self):        pass             def draw(self, surface):        pass  def drawGrid(w, rows, surface):    pass         def redrawWindow(surface):    pass  def randomSnack(rows, item):    pass  def message_box(subject, content):    pass  def main():    pass   main()

2.创造游戏循环:

在所有的游戏中,我们都有一个叫做"主循环"或"游戏循环"的循环。该循环将持续运行,直到游戏退出。它主要负责检查事件,并基于这些事件调用函数和方法。

我们将在main()功能。在函数的顶部声明一些变量,然后进入while循环,这将代表我们的游戏循环。

def main():     global width, rows, s    width = 500  # Width of our screen    height = 500  # Height of our screen    rows = 20  # Amount of rows     win = pygame.display.set_mode((width, height))  # Creates our screen object     s = snake((255,0,0), (10,10))  # Creates a snake object which we will code later      clock = pygame.time.Clock() # creating a clock object     flag = True    # STARTING MAIN LOOP    while flag:        pygame.time.delay(50)  # This will delay the game so it doesn't run too quickly        clock.tick(10)  # Will ensure our game runs at 10 FPS        redrawWindow(win)  # This will refresh our screen

3.更新屏幕:通常,在一个函数或方法中绘制所有对象是一种很好的做法。我们将使用重绘窗口函数来更新显示。我们在游戏循环中每一帧调用一次这个函数。稍后我们将向该函数添加更多内容。然而,现在我们将简单地绘制网格线。

def redrawWindow(surface):    surface.fill((0,0,0))  # Fills the screen with black    drawGrid(surface)  # Will draw our grid lines    pygame.display.update()  # Updates the screen

4.绘制网格:现在将绘制代表20x20网格的线条。

def drawGrid(w, rows, surface):    sizeBtwn = w // rows  # Gives us the distance between the lines     x = 0  # Keeps track of the current x    y = 0  # Keeps track of the current y    for l in range(rows):  # We will draw one vertical and one horizontal line each loop        x = x + sizeBtwn        y = y + sizeBtwn         pygame.draw.line(surface, (255,255,255), (x,0),(x,w))        pygame.draw.line(surface, (255,255,255), (0,y),(w,y))

5.现在当我们运行程序时,我们可以看到网格线被画出来。

6.开始制作贪吃蛇:蛇对象将包含一个代表蛇身体的立方体列表。我们将把这些立方体存储在一个名为body的列表中,它将是一个类变量。我们还将有一个名为turns的类变量。为了开始蛇类,对__init__()方法并添加类变量。

class snake(object):    body = []    turns = {}    def __init__(self, color, pos):        self.color = color        self.head = cube(pos)  # The head will be the front of the snake        self.body.append(self.head)  # We will add head (which is a cube object)        # to our body list         # These will represent the direction our snake is moving        self.dirnx = 0         self.dirny = 1

7.这款游戏最复杂的部分就是翻蛇。我们需要记住我们把我们的蛇转向了哪里和哪个方向,这样当头部后面的立方体到达那个位置时,我们也可以把它们转向。这就是为什么每当我们转向时,我们会将头部的位置添加到转向字典中,其中值是我们转向的方向。这样,当其他立方体到达这个位置时,我们就知道如何转动它们了。

class snake(object):    ...    def move(self):        for event in pygame.event.get():            if event.type == pygame.QUIT:                pygame.quit()             keys = pygame.key.get_pressed()             for key in keys:                if keys[pygame.K_LEFT]:                    self.dirnx = -1                    self.dirny = 0                    self.turns[self.head.pos[:]] = [self.dirnx, self.dirny]                 elif keys[pygame.K_RIGHT]:                    self.dirnx = 1                    self.dirny = 0                    self.turns[self.head.pos[:]] = [self.dirnx, self.dirny]                 elif keys[pygame.K_UP]:                    self.dirnx = 0                    self.dirny = -1                    self.turns[self.head.pos[:]] = [self.dirnx, self.dirny]                 elif keys[pygame.K_DOWN]:                    self.dirnx = 0                    self.dirny = 1                    self.turns[self.head.pos[:]] = [self.dirnx, self.dirny]         for i, c in enumerate(self.body):  # Loop through every cube in our body            p = c.pos[:]  # This stores the cubes position on the grid            if p in self.turns:  # If the cubes current position is one where we turned                turn = self.turns[p]  # Get the direction we should turn                c.move(turn[0],turn[1])  # Move our cube in that direction                if i == len(self.body)-1:  # If this is the last cube in our body remove the turn from the dict                    self.turns.pop(p)            else:  # If we are not turning the cube                # If the cube reaches the edge of the screen we will make it appear on the opposite side                if c.dirnx == -1 and c.pos[0] <= 0: c.pos = (c.rows-1, c.pos[1])                elif c.dirnx == 1 and c.pos[0] >= c.rows-1: c.pos = (0,c.pos[1])                elif c.dirny == 1 and c.pos[1] >= c.rows-1: c.pos = (c.pos[0], 0)                elif c.dirny == -1 and c.pos[1] <= 0: c.pos = (c.pos[0],c.rows-1)                else: c.move(c.dirnx,c.dirny)  # If we haven't reached the edge just move in our current direction

8.画蛇:我们只需画出身体中的每个立方体对象。我们将在蛇身上做这个绘制()方法。

class snake(object):    ...    def draw(self):        for i, c in enumerate(self.body):            if i == 0:  # for the first cube in the list we want to draw eyes                c.draw(surface, True)  # adding the true as an argument will tell us to draw eyes            else:                c.draw(surface)  # otherwise we will just draw a cube

9.结束游戏当我们的蛇物体与自己碰撞时,我们就输了。为了检查这一点,我们在main()游戏循环中的功能。

for x in range(len(s.body)):    if s.body[x].pos in list(map(lambda z:z.pos,s.body[x+1:])): # This will check if any of the positions in our body list overlap        print('Score: ', len(s.body))        message_box('You Lost!', 'Play again...')        s.reset((10,10))        break

10.蛇类-重置()方法现在我们将对重置()方法。所有这些将会做的是重置蛇,这样我们可以在之后再次玩。

class snake():    ...    def reset(self, pos):        self.head = cube(pos)        self.body = []        self.body.append(self.head)        self.turns = {}        self.dirnx = 0        self.dirny = 1

下面我们先看看效果:

好了?蛇蛇大作战就写完啦!

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