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MySQL中如何实现多表查询操作

发表于:2025-01-20 作者:千家信息网编辑
千家信息网最后更新 2025年01月20日,本篇文章给大家分享的是有关MySQL中如何实现多表查询操作,小编觉得挺实用的,因此分享给大家学习,希望大家阅读完这篇文章后可以有所收获,话不多说,跟着小编一起来看看吧。create table dep
千家信息网最后更新 2025年01月20日MySQL中如何实现多表查询操作

本篇文章给大家分享的是有关MySQL中如何实现多表查询操作,小编觉得挺实用的,因此分享给大家学习,希望大家阅读完这篇文章后可以有所收获,话不多说,跟着小编一起来看看吧。

create table department(id int,name varchar(20));create table employee(id int primary key auto_increment,name varchar(20),sex enum('male','female') not null default 'male',age int,dep_id int);
#插入数据insert into department values(200,'技术'),(201,'人力资源'),(202,'销售'),(203,'运营');insert into employee(name,sex,age,dep_id) values('egon','male',18,200),('alex','female',48,201),('wupeiqi','male',38,201),('yuanhao','female',28,202),('nvshen','male',18,200),('xiaomage','female',18,204);
# 查看表结构和数据mysql> desc department;+-------+-------------+------+-----+---------+-------+| Field | Type    | Null | Key | Default | Extra |+-------+-------------+------+-----+---------+-------+| id  | int(11)   | YES |   | NULL  |    || name | varchar(20) | YES |   | NULL  |    |+-------+-------------+------+-----+---------+-------+2 rows in set (0.19 sec)
mysql> desc employee;+--------+-----------------------+------+-----+---------+----------------+| Field | Type         | Null | Key | Default | Extra     |+--------+-----------------------+------+-----+---------+----------------+| id   | int(11)        | NO  | PRI | NULL  | auto_increment || name  | varchar(20)      | YES |   | NULL  |        || sex  | enum('male','female') | NO  |   | male  |        || age  | int(11)        | YES |   | NULL  |        || dep_id | int(11)        | YES |   | NULL  |        |+--------+-----------------------+------+-----+---------+----------------+5 rows in set (0.01 sec)
mysql> select * from department;+------+--------------+| id  | name     |+------+--------------+| 200 | 技术     || 201 | 人力资源   || 202 | 销售     || 203 | 运营     |+------+--------------+4 rows in set (0.02 sec)
mysql> select * from employee;+----+----------+--------+------+--------+| id | name   | sex  | age | dep_id |+----+----------+--------+------+--------+| 1 | egon   | male  |  18 |  200 || 2 | alex   | female |  48 |  201 || 3 | wupeiqi | male  |  38 |  201 || 4 | yuanhao | female |  28 |  202 || 5 | nvshen  | male  |  18 |  200 || 6 | xiaomage | female |  18 |  204 |+----+----------+--------+------+--------+6 rows in set (0.00 sec)

ps:观察两张表,发现department表中id=203部门在employee中没有对应的员工,发现employee中id=6的员工在department表中没有对应关系。

一多表链接查询

SELECT 字段列表
FROM 表1 INNER|LEFT|RIGHT JOIN 表2
ON 表1.字段 = 表2.字段;

(1)先看第一种情况交叉连接:不适用任何匹配条件。生成笛卡尔积.--->重复最多

mysql> select * from employee,department;+----+----------+--------+------+--------+------+--------------+| id | name   | sex  | age | dep_id | id  | name     |+----+----------+--------+------+--------+------+--------------+| 1 | egon   | male  |  18 |  200 | 200 | 技术     || 1 | egon   | male  |  18 |  200 | 201 | 人力资源   || 1 | egon   | male  |  18 |  200 | 202 | 销售     || 1 | egon   | male  |  18 |  200 | 203 | 运营     || 2 | alex   | female |  48 |  201 | 200 | 技术     || 2 | alex   | female |  48 |  201 | 201 | 人力资源   || 2 | alex   | female |  48 |  201 | 202 | 销售     || 2 | alex   | female |  48 |  201 | 203 | 运营     || 3 | wupeiqi | male  |  38 |  201 | 200 | 技术     || 3 | wupeiqi | male  |  38 |  201 | 201 | 人力资源   || 3 | wupeiqi | male  |  38 |  201 | 202 | 销售     || 3 | wupeiqi | male  |  38 |  201 | 203 | 运营     || 4 | yuanhao | female |  28 |  202 | 200 | 技术     || 4 | yuanhao | female |  28 |  202 | 201 | 人力资源   || 4 | yuanhao | female |  28 |  202 | 202 | 销售     || 4 | yuanhao | female |  28 |  202 | 203 | 运营     || 5 | nvshen  | male  |  18 |  200 | 200 | 技术     || 5 | nvshen  | male  |  18 |  200 | 201 | 人力资源   || 5 | nvshen  | male  |  18 |  200 | 202 | 销售     || 5 | nvshen  | male  |  18 |  200 | 203 | 运营     || 6 | xiaomage | female |  18 |  204 | 200 | 技术     || 6 | xiaomage | female |  18 |  204 | 201 | 人力资源   || 6 | xiaomage | female |  18 |  204 | 202 | 销售     || 6 | xiaomage | female |  18 |  204 | 203 | 运营     |

(2)内连接:只连接匹配的行,以双方为基准

#找两张表共有的部分,相当于利用条件从笛卡尔积结果中筛选出了匹配的结果#department没有204这个部门,因而employee表中关于204这条员工信息没有匹配出来mysql> select employee.id,employee.name,employee.age,employee.sex,department.name from employee inner join department on employee.dep_id=department.id;+----+---------+------+--------+--------------+| id | name  | age | sex  | name     |+----+---------+------+--------+--------------+| 1 | egon  |  18 | male  | 技术     || 2 | alex  |  48 | female | 人力资源   || 3 | wupeiqi |  38 | male  | 人力资源   || 4 | yuanhao |  28 | female | 销售     || 5 | nvshen |  18 | male  | 技术     |+----+---------+------+--------+--------------+5 rows in set (0.00 sec)
#上述sql等同于mysql> select employee.id,employee.name,employee.age,employee.sex,department.name from employee,department where employee.dep_id=department.id;

(3)外链接之左连接:优先显示左表全部记录

#以左表为准,即找出所有员工信息,当然包括没有部门的员工#本质就是:在内连接的基础上增加左边有,右边没有的结果mysql> select employee.id,employee.name,department.name as depart_name from employee left join department on employee.dep_id=department.id;+----+----------+--------------+| id | name   | depart_name |+----+----------+--------------+| 1 | egon   | 技术     || 5 | nvshen  | 技术     || 2 | alex   | 人力资源   || 3 | wupeiqi | 人力资源   || 4 | yuanhao | 销售     || 6 | xiaomage | NULL     |+----+----------+--------------+6 rows in set (0.00 sec)

(4) 外链接之右连接:优先显示右表全部记录

#以右表为准,即找出所有部门信息,包括没有员工的部门#本质就是:在内连接的基础上增加右边有,左边没有的结果mysql> select employee.id,employee.name,department.name as depart_name from employee right join department on employee.dep_id=department.id;+------+---------+--------------+| id  | name  | depart_name |+------+---------+--------------+|  1 | egon  | 技术     ||  2 | alex  | 人力资源   ||  3 | wupeiqi | 人力资源   ||  4 | yuanhao | 销售     ||  5 | nvshen | 技术     || NULL | NULL  | 运营     |+------+---------+--------------+6 rows in set (0.00 sec)

(5) 全外连接:显示左右两个表全部记录(了解)

#外连接:在内连接的基础上增加左边有右边没有的和右边有左边没有的结果
#注意:mysql不支持全外连接 full JOIN
#强调:mysql可以使用此种方式间接实现全外连接

语法:select * from employee left join department on employee.dep_id = department.id
union all
select * from employee right join department on employee.dep_id = department.id;

 mysql> select * from employee left join department on employee.dep_id = department.id     union    select * from employee right join department on employee.dep_id = department.id      ;+------+----------+--------+------+--------+------+--------------+| id  | name   | sex  | age | dep_id | id  | name     |+------+----------+--------+------+--------+------+--------------+|  1 | egon   | male  |  18 |  200 | 200 | 技术     ||  5 | nvshen  | male  |  18 |  200 | 200 | 技术     ||  2 | alex   | female |  48 |  201 | 201 | 人力资源   ||  3 | wupeiqi | male  |  38 |  201 | 201 | 人力资源   ||  4 | yuanhao | female |  28 |  202 | 202 | 销售     ||  6 | xiaomage | female |  18 |  204 | NULL | NULL     || NULL | NULL   | NULL  | NULL |  NULL | 203 | 运营     |+------+----------+--------+------+--------+------+--------------+7 rows in set (0.01 sec)#注意 union与union all的区别:union会去掉相同的纪录

二、符合条件连接查询

以内连接的方式查询employee和department表,并且employee表中的age字段值必须大于25,即找出年龄大于25岁的员工以及员工所在的部门

select employee.name,department.name from employee inner join department  on employee.dep_id = department.id  where age > 25;

三、子查询

#1:子查询是将一个查询语句嵌套在另一个查询语句中。
#2:内层查询语句的查询结果,可以为外层查询语句提供查询条件。
#3:子查询中可以包含:IN、NOT IN、ANY、ALL、EXISTS 和 NOT EXISTS等关键字
#4:还可以包含比较运算符:= 、 !=、> 、<等

(1)带in关键字的子查询

#查询平均年龄在25岁以上的部门名select id,name from department  where id in    (select dep_id from employee group by dep_id having avg(age) > 25);# 查看技术部员工姓名select name from employee  where dep_id in    (select id from department where name='技术');#查看不足1人的部门名select name from department  where id not in    (select dep_id from employee group by dep_id);

(2)带比较运算符的子查询

#比较运算符:=、!=、>、>=、<、<=、<>#查询大于所有人平均年龄的员工名与年龄mysql> select name,age from employee where age > (select avg(age) from employee);+---------+------+| name  | age |+---------+------+| alex  |  48 || wupeiqi |  38 |+---------+------+#查询大于部门内平均年龄的员工名、年龄

思路:

(1)先对员工表(employee)中的人员分组(group by),查询出dep_id以及平均年龄。
(2)将查出的结果作为临时表,再对根据临时表的dep_id和employee的dep_id作为筛选条件将employee表和临时表进行内连接。
(3)最后再将employee员工的年龄是大于平均年龄的员工名字和年龄筛选。

mysql> select t1.name,t1.age from employee as t1       inner join      (select dep_id,avg(age) as avg_age from employee group by dep_id) as t2      on t1.dep_id = t2.dep_id      where t1.age > t2.avg_age;+------+------+| name | age |+------+------+| alex |  48 |

(3)带EXISTS关键字的子查询

#EXISTS关字键字表示存在。在使用EXISTS关键字时,内层查询语句不返回查询的记录。而是返回一个真假值。True或False#当返回True时,外层查询语句将进行查询;当返回值为False时,外层查询语句不进行查询#department表中存在dept_id=203,Turemysql> select * from employee where exists (select id from department where id=200);+----+----------+--------+------+--------+| id | name   | sex  | age | dep_id |+----+----------+--------+------+--------+| 1 | egon   | male  |  18 |  200 || 2 | alex   | female |  48 |  201 || 3 | wupeiqi | male  |  38 |  201 || 4 | yuanhao | female |  28 |  202 || 5 | nvshen  | male  |  18 |  200 || 6 | xiaomage | female |  18 |  204 |+----+----------+--------+------+--------+#department表中存在dept_id=205,Falsemysql> select * from employee where exists (select id from department where id=204);Empty set (0.00 sec)

以上就是MySQL中如何实现多表查询操作,小编相信有部分知识点可能是我们日常工作会见到或用到的。希望你能通过这篇文章学到更多知识。更多详情敬请关注行业资讯频道。

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