如何进行mysql多表查询
发表于：2024-11-14 作者：千家信息网编辑
千家信息网最后更新 2024年11月14日，这期内容当中小编将会给大家带来有关如何进行mysql多表查询，文章内容丰富且以专业的角度为大家分析和叙述，阅读完这篇文章希望大家可以有所收获。一、准备数据库init.sql文件内容如下：/* 数据导入
千家信息网最后更新 2024年11月14日如何进行mysql多表查询
这期内容当中小编将会给大家带来有关如何进行mysql多表查询，文章内容丰富且以专业的角度为大家分析和叙述，阅读完这篇文章希望大家可以有所收获。
一、准备数据库
init.sql文件内容如下：
/* 数据导入： Navicat Premium Data Transfer Source Server : localhost Source Server Type : MySQL Source Server Version : 50624 Source Host : localhost Source Database : sqlexam Target Server Type : MySQL Target Server Version : 50624 File Encoding : utf-8 Date: 10/21/2016 06:46:46 AM*/SET NAMES utf8;SET FOREIGN_KEY_CHECKS = 0;-- ------------------------------ Table structure for `class`-- ----------------------------DROP TABLE IF EXISTS `class`;CREATE TABLE `class` ( `cid` int(11) NOT NULL AUTO_INCREMENT, `caption` varchar(32) NOT NULL, PRIMARY KEY (`cid`)) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8;-- ------------------------------ Records of `class`-- ----------------------------BEGIN;INSERT INTO `class` VALUES ('1', '三年二班'), ('2', '三年三班'), ('3', '一年二班'), ('4', '二年九班');COMMIT;-- ------------------------------ Table structure for `course`-- ----------------------------DROP TABLE IF EXISTS `course`;CREATE TABLE `course` ( `cid` int(11) NOT NULL AUTO_INCREMENT, `cname` varchar(32) NOT NULL, `teacher_id` int(11) NOT NULL, PRIMARY KEY (`cid`), KEY `fk_course_teacher` (`teacher_id`), CONSTRAINT `fk_course_teacher` FOREIGN KEY (`teacher_id`) REFERENCES `teacher` (`tid`)) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8;-- ------------------------------ Records of `course`-- ----------------------------BEGIN;INSERT INTO `course` VALUES ('1', '生物', '1'), ('2', '物理', '2'), ('3', '体育', '3'), ('4', '美术', '2');COMMIT;-- ------------------------------ Table structure for `score`-- ----------------------------DROP TABLE IF EXISTS `score`;CREATE TABLE `score` ( `sid` int(11) NOT NULL AUTO_INCREMENT, `student_id` int(11) NOT NULL, `course_id` int(11) NOT NULL, `num` int(11) NOT NULL, PRIMARY KEY (`sid`), KEY `fk_score_student` (`student_id`), KEY `fk_score_course` (`course_id`), CONSTRAINT `fk_score_course` FOREIGN KEY (`course_id`) REFERENCES `course` (`cid`), CONSTRAINT `fk_score_student` FOREIGN KEY (`student_id`) REFERENCES `student` (`sid`)) ENGINE=InnoDB AUTO_INCREMENT=53 DEFAULT CHARSET=utf8;-- ------------------------------ Records of `score`-- ----------------------------BEGIN;INSERT INTO `score` VALUES ('1', '1', '1', '10'), ('2', '1', '2', '9'), ('5', '1', '4', '66'), ('6', '2', '1', '8'), ('8', '2', '3', '68'), ('9', '2', '4', '99'), ('10', '3', '1', '77'), ('11', '3', '2', '66'), ('12', '3', '3', '87'), ('13', '3', '4', '99'), ('14', '4', '1', '79'), ('15', '4', '2', '11'), ('16', '4', '3', '67'), ('17', '4', '4', '100'), ('18', '5', '1', '79'), ('19', '5', '2', '11'), ('20', '5', '3', '67'), ('21', '5', '4', '100'), ('22', '6', '1', '9'), ('23', '6', '2', '100'), ('24', '6', '3', '67'), ('25', '6', '4', '100'), ('26', '7', '1', '9'), ('27', '7', '2', '100'), ('28', '7', '3', '67'), ('29', '7', '4', '88'), ('30', '8', '1', '9'), ('31', '8', '2', '100'), ('32', '8', '3', '67'), ('33', '8', '4', '88'), ('34', '9', '1', '91'), ('35', '9', '2', '88'), ('36', '9', '3', '67'), ('37', '9', '4', '22'), ('38', '10', '1', '90'), ('39', '10', '2', '77'), ('40', '10', '3', '43'), ('41', '10', '4', '87'), ('42', '11', '1', '90'), ('43', '11', '2', '77'), ('44', '11', '3', '43'), ('45', '11', '4', '87'), ('46', '12', '1', '90'), ('47', '12', '2', '77'), ('48', '12', '3', '43'), ('49', '12', '4', '87'), ('52', '13', '3', '87');COMMIT;-- ------------------------------ Table structure for `student`-- ----------------------------DROP TABLE IF EXISTS `student`;CREATE TABLE `student` ( `sid` int(11) NOT NULL AUTO_INCREMENT, `gender` char(1) NOT NULL, `class_id` int(11) NOT NULL, `sname` varchar(32) NOT NULL, PRIMARY KEY (`sid`), KEY `fk_class` (`class_id`), CONSTRAINT `fk_class` FOREIGN KEY (`class_id`) REFERENCES `class` (`cid`)) ENGINE=InnoDB AUTO_INCREMENT=17 DEFAULT CHARSET=utf8;-- ------------------------------ Records of `student`-- ----------------------------BEGIN;INSERT INTO `student` VALUES ('1', '男', '1', '理解'), ('2', '女', '1', '钢蛋'), ('3', '男', '1', '张三'), ('4', '男', '1', '张一'), ('5', '女', '1', '张二'), ('6', '男', '1', '张四'), ('7', '女', '2', '铁锤'), ('8', '男', '2', '李三'), ('9', '男', '2', '李一'), ('10', '女', '2', '李二'), ('11', '男', '2', '李四'), ('12', '女', '3', '如花'), ('13', '男', '3', '刘三'), ('14', '男', '3', '刘一'), ('15', '女', '3', '刘二'), ('16', '男', '3', '刘四');COMMIT;-- ------------------------------ Table structure for `teacher`-- ----------------------------DROP TABLE IF EXISTS `teacher`;CREATE TABLE `teacher` ( `tid` int(11) NOT NULL AUTO_INCREMENT, `tname` varchar(32) NOT NULL, PRIMARY KEY (`tid`)) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=utf8;-- ------------------------------ Records of `teacher`-- ----------------------------BEGIN;INSERT INTO `teacher` VALUES ('1', '张磊老师'), ('2', '李平老师'), ('3', '刘海燕老师'), ('4', '朱云海老师'), ('5', '李杰老师');COMMIT;SET FOREIGN_KEY_CHECKS = 1;1、创建数据库并导入数据
mysql> create database db1;
mysql> create database db1;
mysql> use db1;
mysql> source /root/init.sql
2、查看表
mysql> show tables;+---------------+| Tables_in_db1 |+---------------+| class || course || score || student || teacher |+---------------+mysql> select * from class;+-----+--------------+| cid | caption |+-----+--------------+| 1 | 三年二班 || 2 | 三年三班 || 3 | 一年二班 || 4 | 二年九班 |+-----+--------------+mysql> select * from course;+-----+--------+------------+| cid | cname | teacher_id |+-----+--------+------------+| 1 | 生物 | 1 || 2 | 物理 | 2 || 3 | 体育 | 3 || 4 | 美术 | 2 |+-----+--------+------------+mysql> select * from teacher;+-----+-----------------+| tid | tname |+-----+-----------------+| 1 | 张磊老师 || 2 | 李平老师 || 3 | 刘海燕老师 || 4 | 朱云海老师 || 5 | 李杰老师 |+-----+-----------------+mysql> select * from student;+-----+--------+----------+--------+| sid | gender | class_id | sname |+-----+--------+----------+--------+| 1 | 男 | 1 | 理解 || 2 | 女 | 1 | 钢蛋 || 3 | 男 | 1 | 张三 || 4 | 男 | 1 | 张一 || 5 | 女 | 1 | 张二 || 6 | 男 | 1 | 张四 || 7 | 女 | 2 | 铁锤 || 8 | 男 | 2 | 李三 || 9 | 男 | 2 | 李一 || 10 | 女 | 2 | 李二 || 11 | 男 | 2 | 李四 || 12 | 女 | 3 | 如花 || 13 | 男 | 3 | 刘三 || 14 | 男 | 3 | 刘一 || 15 | 女 | 3 | 刘二 || 16 | 男 | 3 | 刘四 |+-----+--------+----------+--------+mysql> select * from score;+-----+------------+-----------+-----+| sid | student_id | course_id | num |+-----+------------+-----------+-----+| 1 | 1 | 1 | 10 || 2 | 1 | 2 | 9 || 5 | 1 | 4 | 66 || 6 | 2 | 1 | 8 || 8 | 2 | 3 | 68 || 9 | 2 | 4 | 99 || 10 | 3 | 1 | 77 || 11 | 3 | 2 | 66 || 12 | 3 | 3 | 87 || 13 | 3 | 4 | 99 || 14 | 4 | 1 | 79 || 15 | 4 | 2 | 11 || 16 | 4 | 3 | 67 || 17 | 4 | 4 | 100 || 18 | 5 | 1 | 79 || 19 | 5 | 2 | 11 || 20 | 5 | 3 | 67 || 21 | 5 | 4 | 100 || 22 | 6 | 1 | 9 || 23 | 6 | 2 | 100 || 24 | 6 | 3 | 67 || 25 | 6 | 4 | 100 || 26 | 7 | 1 | 9 || 27 | 7 | 2 | 100 || 28 | 7 | 3 | 67 || 29 | 7 | 4 | 88 || 30 | 8 | 1 | 9 || 31 | 8 | 2 | 100 || 32 | 8 | 3 | 67 || 33 | 8 | 4 | 88 || 34 | 9 | 1 | 91 || 35 | 9 | 2 | 88 || 36 | 9 | 3 | 67 || 37 | 9 | 4 | 22 || 38 | 10 | 1 | 90 || 39 | 10 | 2 | 77 || 40 | 10 | 3 | 43 || 41 | 10 | 4 | 87 || 42 | 11 | 1 | 90 || 43 | 11 | 2 | 77 || 44 | 11 | 3 | 43 || 45 | 11 | 4 | 87 || 46 | 12 | 1 | 90 || 47 | 12 | 2 | 77 || 48 | 12 | 3 | 43 || 49 | 12 | 4 | 87 || 52 | 13 | 3 | 87 |+-----+------------+-----------+-----+
二、操作练习
1、查询所有的课程的名称以及对应的任课老师姓名
SELECT course.cname,teacher.tname FROM course INNER JOIN teacher ON course.teacher_id = teacher.tid;SELECT course.cname,teacher.tname FROM course JOIN teacher ON course.teacher_id = teacher.tid;+--------+-----------------+| cname | tname |+--------+-----------------+| 生物 | 张磊老师 || 物理 | 李平老师 || 美术 | 李平老师 || 体育 | 刘海燕老师 |+--------+-----------------+
2、查询学生表中男女生各有多少人
SELECT gender 性别,count(1) 人数 FROM student GROUP BY gender;+--------+--------+| 性别 | 人数 |+--------+--------+| 女 | 6 || 男 | 10 |+--------+--------+
3、查询物理成绩等于100的学生的姓名
SELECT student.sname FROM student WHERE sid IN ( SELECT student_id FROM score INNER JOIN course ON score.course_id = course.cid WHERE course.cname = '物理' AND score.num = 100);+--------+| sname |+--------+| 张四 || 铁锤 || 李三 |+--------+
4、查询平均成绩大于八十分的同学的姓名和平均成绩
SELECT student.sname,t1.avg_num FROM student INNER JOIN ( SELECT student_id,avg(num) AS avg_num FROM score GROUP BY student_id HAVING avg(num) > 80) AS t1 ON student.sid = t1.student_id; +--------+---------+| sname | avg_num |+--------+---------+| 张三 | 82.2500 || 刘三 | 87.0000 |+--------+---------+SELECT student.sname, avg(num) AS avg_num FROM score JOIN student ON student.sid = score.student_id GROUP BY student_id HAVING avg_num > 80;
5、查询所有学生的学号，姓名，选课数，总成绩
SELECT student.sid,student.sname,t1.course_num,t1.total_num FROM student LEFT JOIN ( SELECT student_id,COUNT(course_id) course_num,sum(num) total_num FROM score GROUP BY student_id) AS t1 ON student.sid = t1.student_id;+-----+--------+------------+-----------+| sid | sname | course_num | total_num |+-----+--------+------------+-----------+| 1 | 理解 | 3 | 85 || 2 | 钢蛋 | 3 | 175 || 3 | 张三 | 4 | 329 || 4 | 张一 | 4 | 257 || 5 | 张二 | 4 | 257 || 6 | 张四 | 4 | 276 || 7 | 铁锤 | 4 | 264 || 8 | 李三 | 4 | 264 || 9 | 李一 | 4 | 268 || 10 | 李二 | 4 | 297 || 11 | 李四 | 4 | 297 || 12 | 如花 | 4 | 297 || 13 | 刘三 | 1 | 87 || 14 | 刘一 | NULL | NULL || 15 | 刘二 | NULL | NULL || 16 | 刘四 | NULL | NULL |+-----+--------+------------+-----------+
6、 查询姓李老师的个数
SELECT count(tid) FROM teacher WHERE tname LIKE '李%';+------------+| count(tid) |+------------+| 2 |+------------+
7、 查询没有报李平老师课的学生姓名
SELECT student.sname FROM student WHERE sid NOT IN ( SELECT DISTINCT student_id FROM score WHERE course_id IN ( SELECT course.cid FROM course INNER JOIN teacher ON course.teacher_id = teacher.tid WHERE teacher.tname = '李平老师' ));+--------+| sname |+--------+| 刘三 || 刘一 || 刘二 || 刘四 |+--------+
8、 查询物理课程比生物课程高的学生的学号
SELECT t1.student_id FROM (SELECT student_id,num FROM score WHERE course_id = (SELECT cid FROM course WHERE cname = '物理')) AS t1INNER JOIN ( SELECT student_id,num FROM score WHERE course_id = (SELECT cid FROM course WHERE cname = '生物')) AS t2 ON t1.student_id = t2.student_id WHERE t1.num > t2.num;+------------+| student_id |+------------+| 6 || 7 || 8 |+------------+
9、 查询没有同时选修物理课程和体育课程的学生姓名
SELECT student.sname FROM student WHERE sid IN ( SELECT student_id FROM score WHERE course_id IN (SELECT cid FROM course WHERE cname = '物理' OR cname = '体育') GROUP BY student_id HAVING COUNT(course_id) = 1);+--------+| sname |+--------+| 理解 || 钢蛋 || 刘三 |+--------+
10、查询挂科超过两门(包括两门)的学生姓名和班级
SELECT student.sname,class.caption FROM student INNER JOIN ( SELECT student_id FROM score WHERE num < 60 GROUP BY student_id HAVING count(course_id) >= 2) AS t1INNER JOIN class ON student.sid = t1.student_id AND student.class_id = class.cid;+--------+--------------+| sname | caption |+--------+--------------+| 理解 | 三年二班 |+--------+--------------+
11、查询选修了所有课程的学生姓名
SELECT student.sname FROM student WHERE sid IN ( SELECT student_id FROM score GROUP BY student_id HAVING COUNT(course_id) = (SELECT count(cid) FROM course));+--------+| sname |+--------+| 张三 || 张一 || 张二 || 张四 || 铁锤 || 李三 || 李一 || 李二 || 李四 || 如花 |+--------+
12、查询李平老师教的课程的所有成绩记录
SELECT * FROM score WHERE course_id IN (SELECT cid FROM course INNER JOIN teacher ON course.teacher_id = teacher.tid WHERE teacher.tname = '李平老师');+-----+------------+-----------+-----+| sid | student_id | course_id | num |+-----+------------+-----------+-----+| 2 | 1 | 2 | 9 || 11 | 3 | 2 | 66 || 15 | 4 | 2 | 11 || 19 | 5 | 2 | 11 || 23 | 6 | 2 | 100 || 27 | 7 | 2 | 100 || 31 | 8 | 2 | 100 || 35 | 9 | 2 | 88 || 39 | 10 | 2 | 77 || 43 | 11 | 2 | 77 || 47 | 12 | 2 | 77 || 5 | 1 | 4 | 66 || 9 | 2 | 4 | 99 || 13 | 3 | 4 | 99 || 17 | 4 | 4 | 100 || 21 | 5 | 4 | 100 || 25 | 6 | 4 | 100 || 29 | 7 | 4 | 88 || 33 | 8 | 4 | 88 || 37 | 9 | 4 | 22 || 41 | 10 | 4 | 87 || 45 | 11 | 4 | 87 || 49 | 12 | 4 | 87 |+-----+------------+-----------+-----+
13、查询全部学生都选修了的课程号和课程名
SELECT cid,cname FROM course WHERE cid IN ( SELECT course_id FROM score GROUP BY course_id HAVING COUNT(student_id) = (SELECT COUNT(sid) FROM student));
14、查询每门课程被选修的次数
SELECT course_id,COUNT(student_id) FROM score GROUP BY course_id;+-----------+-------------------+| course_id | COUNT(student_id) |+-----------+-------------------+| 1 | 12 || 2 | 11 || 3 | 12 || 4 | 12 |+-----------+-------------------+
15、查询之选修了一门课程的学生姓名和学号
SELECT sid,sname FROM student WHERE sid IN (SELECT student_id FROM score GROUP BY student_id HAVING COUNT(course_id) = 1);+-----+--------+| sid | sname |+-----+--------+| 13 | 刘三 |+-----+--------+
16、查询所有学生考出的成绩并按从高到低排序（成绩去重）
SELECT DISTINCT num FROM score ORDER BY num DESC;+-----+| num |+-----+| 100 || 99 || 91 || 90 || 88 || 87 || 79 || 77 || 68 || 67 || 66 || 43 || 22 || 11 || 10 || 9 || 8 |+-----+
17、查询平均成绩大于85的学生姓名和平均成绩
SELECT sname,t1.avg_num FROM student INNER JOIN ( SELECT student_id,avg(num) avg_num FROM score GROUP BY student_id HAVING AVG(num) > 85) t1 ON student.sid = t1.student_id;+--------+---------+| sname | avg_num |+--------+---------+| 刘三 | 87.0000 |+--------+---------+
18、查询生物成绩不及格的学生姓名和对应生物分数
SELECT sname 姓名,num 生物成绩 FROM scoreLEFT JOIN course ON score.course_id = course.cidLEFT JOIN student ON score.student_id = student.sidWHERE course.cname = '生物' AND score.num < 60;+--------+--------------+| 姓名 | 生物成绩 |+--------+--------------+| 理解 | 10 || 钢蛋 | 8 || 张四 | 9 || 铁锤 | 9 || 李三 | 9 |+--------+--------------+
19、查询在所有选修了李平老师课程的学生中，这些课程(李平老师的课程，不是所有课程)平均成绩最高的学生姓名
SELECT sname FROM student WHERE sid = ( SELECT student_id FROM score WHERE course_id IN ( SELECT course.cid FROM course INNER JOIN teacher ON course.teacher_id = teacher.tid WHERE teacher.tname = '李平老师') GROUP BY student_id ORDER BY AVG(num) DESC LIMIT 1 );+--------+| sname |+--------+| 张四 |+--------+
20、查询每门课程成绩最好的前两名学生姓名
#查看每门课程按照分数排序的信息，为下列查找正确与否提供依据SELECT * FROM score ORDER BY course_id,num DESC;+-----+------------+-----------+-----+| sid | student_id | course_id | num |+-----+------------+-----------+-----+| 34 | 9 | 1 | 91 || 46 | 12 | 1 | 90 || 42 | 11 | 1 | 90 || 38 | 10 | 1 | 90 || 14 | 4 | 1 | 79 || 18 | 5 | 1 | 79 || 10 | 3 | 1 | 77 || 1 | 1 | 1 | 10 || 30 | 8 | 1 | 9 || 26 | 7 | 1 | 9 || 22 | 6 | 1 | 9 || 6 | 2 | 1 | 8 || 31 | 8 | 2 | 100 || 23 | 6 | 2 | 100 || 27 | 7 | 2 | 100 || 35 | 9 | 2 | 88 || 47 | 12 | 2 | 77 || 43 | 11 | 2 | 77 || 39 | 10 | 2 | 77 || 11 | 3 | 2 | 66 || 19 | 5 | 2 | 11 || 15 | 4 | 2 | 11 || 2 | 1 | 2 | 9 || 52 | 13 | 3 | 87 || 12 | 3 | 3 | 87 || 8 | 2 | 3 | 68 || 20 | 5 | 3 | 67 || 36 | 9 | 3 | 67 || 16 | 4 | 3 | 67 || 24 | 6 | 3 | 67 || 32 | 8 | 3 | 67 || 28 | 7 | 3 | 67 || 48 | 12 | 3 | 43 || 44 | 11 | 3 | 43 || 40 | 10 | 3 | 43 || 21 | 5 | 4 | 100 || 17 | 4 | 4 | 100 || 25 | 6 | 4 | 100 || 9 | 2 | 4 | 99 || 13 | 3 | 4 | 99 || 29 | 7 | 4 | 88 || 33 | 8 | 4 | 88 || 41 | 10 | 4 | 87 || 49 | 12 | 4 | 87 || 45 | 11 | 4 | 87 || 5 | 1 | 4 | 66 || 37 | 9 | 4 | 22 |+-----+------------+-----------+-----+#表1：求出每门课程的课程course_id,与最高分数first_numSELECT course_id,max(num) first_num FROM score GROUP BY course_id;+-----------+-----------+| course_id | first_num |+-----------+-----------+| 1 | 91 || 2 | 100 || 3 | 87 || 4 | 100 |+-----------+-----------+#表2：去掉最高分，再按照课程分组，取得的最高分，就是第二高的分数second_numSELECT score.course_id,max(num) second_num FROM score INNER JOIN ( SELECT course_id,max(num) first_num FROM score GROUP BY course_id) AS t ON score.course_id = t.course_idWHERE score.num < t.first_num GROUP BY course_id;+-----------+------------+| course_id | second_num |+-----------+------------+| 1 | 90 || 2 | 88 || 3 | 68 || 4 | 99 |+-----------+------------+#将表1和表2联合到一起，得到一张表t3，包含课程course_id与该们课程的first_num与second_numSELECT t1.course_id,t1.first_num,t2.second_num FROM (SELECT course_id, max(num) first_num FROM score GROUP BY course_id) AS t1 INNER JOIN ( SELECT score.course_id,max(num) second_num FROM score INNER JOIN ( SELECT course_id,max(num) first_num FROM score GROUP BY course_id) AS t ON score.course_id = t.course_id WHERE score.num < t.first_num GROUP BY course_id ) AS t2 ON t1.course_id = t2.course_id;+-----------+-----------+------------+| course_id | first_num | second_num |+-----------+-----------+------------+| 1 | 91 | 90 || 2 | 100 | 88 || 3 | 87 | 68 || 4 | 100 | 99 |+-----------+-----------+------------+#查询前两名的学生（有可能出现并列第一或者并列第二的情况）SELECT score.student_id,t3.course_id,t3.first_num,t3.second_num FROM score INNER JOIN ( SELECT t1.course_id,t1.first_num,t2.second_num FROM ( SELECT course_id,max(num) first_num FROM score GROUP BY course_id) AS t1 INNER JOIN ( SELECT score.course_id,max(num) second_num FROM score INNER JOIN (SELECT course_id, max(num) first_num FROM score GROUP BY course_id) AS t ON score.course_id = t.course_id WHERE score.num < t.first_num GROUP BY course_id) AS t2 ON t1.course_id = t2.course_id) AS t3 ON score.course_id = t3.course_id WHERE score.num >= t3.second_num AND score.num <= t3.first_num;+------------+-----------+-----------+------------+| student_id | course_id | first_num | second_num |+------------+-----------+-----------+------------+| 2 | 3 | 87 | 68 || 2 | 4 | 100 | 99 || 3 | 3 | 87 | 68 || 3 | 4 | 100 | 99 || 4 | 4 | 100 | 99 || 5 | 4 | 100 | 99 || 6 | 2 | 100 | 88 || 6 | 4 | 100 | 99 || 7 | 2 | 100 | 88 || 8 | 2 | 100 | 88 || 9 | 1 | 91 | 90 || 9 | 2 | 100 | 88 || 10 | 1 | 91 | 90 || 11 | 1 | 91 | 90 || 12 | 1 | 91 | 90 || 13 | 3 | 87 | 68 |+------------+-----------+-----------+------------+#排序后可以看的明显点SELECT score.student_id,t3.course_id,t3.first_num,t3.second_num FROM score INNER JOIN ( SELECT t1.course_id,t1.first_num,t2.second_num FROM ( SELECT course_id,max(num) first_num FROM score GROUP BY course_id) AS t1 INNER JOIN ( SELECT score.course_id,max(num) second_num FROM score INNER JOIN (SELECT course_id,max(num) first_num FROM score GROUP BY course_id) AS t ON score.course_id = t.course_id WHERE score.num < t.first_num GROUP BY course_id) AS t2 ON t1.course_id = t2.course_id) AS t3 ON score.course_id = t3.course_idWHERE score.num >= t3.second_num AND score.num <= t3.first_num ORDER BY course_id;+------------+-----------+-----------+------------+| student_id | course_id | first_num | second_num |+------------+-----------+-----------+------------+| 9 | 1 | 91 | 90 || 10 | 1 | 91 | 90 || 11 | 1 | 91 | 90 || 12 | 1 | 91 | 90 || 8 | 2 | 100 | 88 || 9 | 2 | 100 | 88 || 6 | 2 | 100 | 88 || 7 | 2 | 100 | 88 || 2 | 3 | 87 | 68 || 3 | 3 | 87 | 68 || 13 | 3 | 87 | 68 || 2 | 4 | 100 | 99 || 3 | 4 | 100 | 99 || 4 | 4 | 100 | 99 || 5 | 4 | 100 | 99 || 6 | 4 | 100 | 99 |+------------+-----------+-----------+------------+
21、查询不同课程但成绩相同的学号，课程号，成绩
select distinct t1.student_id,t1.course_id,t1.num from score t1,(select student_id,course_id, num from score) t2 where t1.num=t2.num and t1.course_id <>t2.course_id order by num;+------------+-----------+-----+| student_id | course_id | num |+------------+-----------+-----+| 6 | 1 | 9 || 7 | 1 | 9 || 8 | 1 | 9 || 1 | 2 | 9 || 1 | 4 | 66 || 3 | 2 | 66 || 12 | 2 | 77 || 10 | 2 | 77 || 3 | 1 | 77 || 11 | 2 | 77 || 3 | 3 | 87 || 11 | 4 | 87 || 12 | 4 | 87 || 13 | 3 | 87 || 10 | 4 | 87 || 7 | 4 | 88 || 8 | 4 | 88 || 9 | 2 | 88 || 4 | 4 | 100 || 5 | 4 | 100 || 6 | 2 | 100 || 6 | 4 | 100 || 7 | 2 | 100 || 8 | 2 | 100 |+------------+-----------+-----+
22、查询没学过"叶平"老师课程的学生姓名以及选修的课程名称；
SELECT student.sname,course.cname FROM student,course WHERE sid NOT IN ( SELECT DISTINCT student_id FROM score WHERE course_id IN ( SELECT course.cid FROM course INNER JOIN teacher ON course.teacher_id = teacher.tid WHERE teacher.tname = '叶平老师' ));+--------+--------+| sname | cname |+--------+--------+| 理解 | 生物 || 理解 | 物理 || 理解 | 体育 || 理解 | 美术 || 钢蛋 | 生物 || 钢蛋 | 物理 || 钢蛋 | 体育 || 钢蛋 | 美术 || 张三 | 生物 || 张三 | 物理 || 张三 | 体育 || 张三 | 美术 || 张一 | 生物 || 张一 | 物理 || 张一 | 体育 || 张一 | 美术 || 张二 | 生物 || 张二 | 物理 || 张二 | 体育 || 张二 | 美术 || 张四 | 生物 || 张四 | 物理 || 张四 | 体育 || 张四 | 美术 || 铁锤 | 生物 || 铁锤 | 物理 || 铁锤 | 体育 || 铁锤 | 美术 || 李三 | 生物 || 李三 | 物理 || 李三 | 体育 || 李三 | 美术 || 李一 | 生物 || 李一 | 物理 || 李一 | 体育 || 李一 | 美术 || 李二 | 生物 || 李二 | 物理 || 李二 | 体育 || 李二 | 美术 || 李四 | 生物 || 李四 | 物理 || 李四 | 体育 || 李四 | 美术 || 如花 | 生物 || 如花 | 物理 || 如花 | 体育 || 如花 | 美术 || 刘三 | 生物 || 刘三 | 物理 || 刘三 | 体育 || 刘三 | 美术 || 刘一 | 生物 || 刘一 | 物理 || 刘一 | 体育 || 刘一 | 美术 || 刘二 | 生物 || 刘二 | 物理 || 刘二 | 体育 || 刘二 | 美术 || 刘四 | 生物 || 刘四 | 物理 || 刘四 | 体育 || 刘四 | 美术 |+--------+--------+
23、查询所有选修了学号为1的同学选修过的一门或者多门课程的同学学号和姓名；
SELECT sid,sname FROM student WHERE sid in (SELECT DISTINCT student_id FROM score WHERE course_id in (SELECT course_id FROM score WHERE student_id=1));+-----+--------+| sid | sname |+-----+--------+| 1 | 理解 || 2 | 钢蛋 || 3 | 张三 || 4 | 张一 || 5 | 张二 || 6 | 张四 || 7 | 铁锤 || 8 | 李三 || 9 | 李一 || 10 | 李二 || 11 | 李四 || 12 | 如花 |+-----+--------+
24、任课最多的老师中学生单科成绩最高的学生姓名
SELECT sname FROM student WHERE sid IN (SELECT student_id FROM score,(SELECT course_id,MAX(num) 最大值 FROM score WHERE course_id in (SELECT cid FROM course WHERE teacher_id=(SELECT teacher_id FROM course GROUP BY teacher_id ORDER BY COUNT(cid) DESC LIMIT 1)) GROUP BY course_id HAVING max(num)) A WHERE A.最大值=score.num AND score.course_id=A.course_id);+--------+| sname |+--------+| 张一 || 张二 || 张四 || 铁锤 || 李三 |+--------+
上述就是小编为大家分享的如何进行mysql多表查询了，如果刚好有类似的疑惑，不妨参照上述分析进行理解。如果想知道更多相关知识，欢迎关注行业资讯频道。
课程
查询
生物
老师
物理
体育
美术
姓名
学生
成绩
铁锤
李平
张三
李一
李二
李四
如花
刘一
学号
最高
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