varchar类型的字段存储纯数字的排序

千家信息网最后更新 2025年02月04日varchar类型的字段存储纯数字的排序如果表字段的类型为varchar型，但是里面存储的是纯数字，怎么实现按照数字的大小来排序？
下面的方法对于mysql和oracle都实用
order by 字段+0
order by 字段*1
等等都可以实现

mysql> create table tn (id varchar(30),name varchar(50));
mysql> show create table tn;
+-------+-----------------------------------------------------------------------------------------------------------------------------+
| Table | Create Table |
+-------+-----------------------------------------------------------------------------------------------------------------------------+
| tn | CREATE TABLE `tn` (
`id` varchar(30) DEFAULT NULL,
`name` varchar(50) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8 |


mysql> insert into tn values (1,'a');
Query OK, 1 row affected (0.01 sec)


mysql> insert into tn values (10,'b');
Query OK, 1 row affected (0.00 sec)


mysql> insert into tn values (11,'bb');
Query OK, 1 row affected (0.00 sec)


mysql> insert into tn values (2,'bb');
Query OK, 1 row affected (0.00 sec)


mysql> insert into tn values (5,'c');
Query OK, 1 row affected (0.00 sec)


mysql> insert into tn values (3,'f');
Query OK, 1 row affected (0.00 sec)


mysql> insert into tn values (6,'g');
Query OK, 1 row affected (0.00 sec)


mysql> select * from tn;

+------+------+
| id | name |
+------+------+
| 1 | a |
| 10 | b |
| 11 | bb |
| 2 | bb |
| 5 | c |
| 3 | f |
| 6 | g |
+------+------+

使用order by语句进行排序
mysql> select * from tn order by id desc;
+------+------+
| id | name |
+------+------+
| 6 | g |
| 5 | c |
| 3 | f |
| 2 | bb |
| 11 | bb |
| 10 | b |
| 1 | a |
+------+------+
7 rows in set (0.00 sec)

貌似是不起作用，因为id列的值存的是字符串类型的
解决：
使用字段+0解决

mysql> select * from tn order by id+0 desc;
+------+------+
| id | name |
+------+------+
| 11 | bb |
| 10 | b |
| 6 | g |
| 5 | c |
| 3 | f |
| 2 | bb |
| 1 | a |
+------+------+
7 rows in set (0.00 sec)

或者使用 字段*1解决
mysql> select * from tn order by id*1 desc;
+------+------+
| id | name |
+------+------+
| 11 | bb |
| 10 | b |
| 6 | g |
| 5 | c |
| 3 | f |
| 2 | bb |
| 1 | a |
+------+------+
7 rows in set (0.00 sec)