Oracle通过函数进行进制转化

十六进制转化为十进制：to_number()

SQL> select to_number('a','x') from dual;TO_NUMBER('A','X')------------------                10

十进制转化为十六进制：to_char()

SQL> select to_char(10,'xxx') from dual;TO_CHAR(10,'------------   a

二进制没有办法直接转化可以通过函数实现：

十进制转化为二进制

CREATE OR REPLACE FUNCTION NUMBER_TO_BIT(V_NUM NUMBER)RETURN VARCHAR IS V_RTN VARCHAR(8);--注意返回列长度  V_N1  NUMBER;  V_N2  NUMBER;BEGINV_N1 := V_NUM;    LOOP      V_N2  := MOD(V_N1, 2);      V_N1  := ABS(TRUNC(V_N1 / 2)); --取商的绝对值      V_RTN := TO_CHAR(V_N2) || V_RTN;      EXIT WHEN V_N1 = 0;    END LOOP;--返回二进制长度 SELECT lpad(V_RTN,8,0) --八位不足补0    INTO   V_RTN    FROM dual;return V_RTN;end;

二进制转化为十进制：

CREATE OR REPLACE FUNCTION BIT_TO_NUMBER(P_BIN IN VARCHAR2) RETURN NUMBER AS  V_SQL VARCHAR2(30000) := 'SELECT BIN_TO_NUM(';  V_RETURN NUMBER;BEGIN  IF LENGTH(P_BIN) >= 256 THEN    RAISE_APPLICATION_ERROR(-20001, 'INPUT BIN TOO LONG!');  END IF;  IF LTRIM(P_BIN, '01') IS NOT NULL THEN    RAISE_APPLICATION_ERROR(-20002, 'INPUT STR IS NOT VALID BIN VALUE!');  END IF;  FOR I IN 1 .. LENGTH(P_BIN) LOOP    V_SQL := V_SQL || SUBSTR(P_BIN, I, 1) || ',';  END LOOP;  V_SQL := RTRIM(V_SQL, ',') || ') FROM DUAL';  EXECUTE IMMEDIATE V_SQL    INTO V_RETURN;  RETURN V_RETURN;END;

创建函数同义词

create public synonym number_to_bit for number_to_bit;grant execute on number_to_bit to public

十六转二和二转十六，则可以结合十转十六函数和二转十函数进行，这里不在额外举例。

ASCII码及ORACLE元数据转换函数：RAWTOHEX和HEXTORAW

SQL> select rawtohex(1) from dual;RAWTOHEX(1)------------C102SQL> select rawtohex('1') from dual;RAWTOH------31SQL> select rawtohex('a') from dual;RAWTOH------61SQL> select rawtohex('A') from dual;RAWTOH------41SQL> select hextoraw('A') from dual;HE--0ASQL> select hextoraw('1') from dual;HE--01