oracle 身份证校验函数的实例代码

1、正则表达式写法：

CREATE OR REPLACE FUNCTION Func_checkidcard (p_idcard IN VARCHAR2) RETURN INTIS  v_regstr   VARCHAR2 (2000);  v_sum     NUMBER;  v_mod     NUMBER;  v_checkcode  CHAR (11)    := '10X98765432';  v_checkbit  CHAR (1);  v_areacode  VARCHAR2 (2000) := '11,12,13,14,15,21,22,23,31,32,33,34,35,36,37,41,42,43,44,45,46,50,51,52,53,54,61,62,63,64,65,71,81,82,91,';BEGIN  CASE LENGTHB (p_idcard)   WHEN 15   THEN                              -- 15位     IF INSTRB (v_areacode, SUBSTR (p_idcard, 1, 2) || ',') = 0 THEN      RETURN 0;     END IF;     IF MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 2)) + 1900, 400) = 0      OR       (        MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 2)) + 1900, 100) <> 0        AND         MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 2)) + 1900, 4) = 0      )     THEN                             -- 闰年      v_regstr :=        '^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}$';     ELSE      v_regstr :=        '^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}$';     END IF;     IF REGEXP_LIKE (p_idcard, v_regstr) THEN      RETURN 1;     ELSE      RETURN 0;     END IF;   WHEN 18   THEN                               -- 18位     IF INSTRB (v_areacode, SUBSTRB (p_idcard, 1, 2) || ',') = 0 THEN      RETURN 0;     END IF;         IF MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 4)), 400) = 0      OR       (        MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 4)), 100) <> 0        AND         MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 4)), 4) = 0      )     THEN                             -- 闰年      v_regstr :=        '^[1-9][0-9]{5}(19|20)[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}[0-9Xx]$';     ELSE      v_regstr :=        '^[1-9][0-9]{5}(19|20)[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}[0-9Xx]$';     END IF;     IF REGEXP_LIKE (p_idcard, v_regstr) THEN      v_sum :=          ( TO_NUMBER (SUBSTRB (p_idcard, 1, 1))          + TO_NUMBER (SUBSTRB (p_idcard, 11, 1))          )         * 7        +  ( TO_NUMBER (SUBSTRB (p_idcard, 2, 1))          + TO_NUMBER (SUBSTRB (p_idcard, 12, 1))          )         * 9        +  ( TO_NUMBER (SUBSTRB (p_idcard, 3, 1))          + TO_NUMBER (SUBSTRB (p_idcard, 13, 1))          )         * 10        +  ( TO_NUMBER (SUBSTRB (p_idcard, 4, 1))          + TO_NUMBER (SUBSTRB (p_idcard, 14, 1))          )         * 5        +  ( TO_NUMBER (SUBSTRB (p_idcard, 5, 1))          + TO_NUMBER (SUBSTRB (p_idcard, 15, 1))          )         * 8        +  ( TO_NUMBER (SUBSTRB (p_idcard, 6, 1))          + TO_NUMBER (SUBSTRB (p_idcard, 16, 1))          )         * 4        +  ( TO_NUMBER (SUBSTRB (p_idcard, 7, 1))          + TO_NUMBER (SUBSTRB (p_idcard, 17, 1))          )         * 2        + TO_NUMBER (SUBSTRB (p_idcard, 8, 1)) * 1        + TO_NUMBER (SUBSTRB (p_idcard, 9, 1)) * 6        + TO_NUMBER (SUBSTRB (p_idcard, 10, 1)) * 3;      v_mod := MOD (v_sum, 11);      v_checkbit := SUBSTRB (v_checkcode, v_mod + 1, 1);      IF v_checkbit = upper(substrb(p_idcard,18,1)) THEN        RETURN 1;      ELSE        RETURN 0;      END IF;     ELSE      RETURN 0;     END IF;   ELSE     RETURN 0;  -- 身份证号码位数不对  END CASE;EXCEPTION  WHEN OTHERS  THEN   RETURN 0;END fn_checkidcard;/Show Err;

2、非正则表达式写法

Create Or Replace Function Func_checkIdcard (p_idcard in varchar2) Return NumberIs  v_sum     Number;  v_mod     Number;  v_length   Number;  v_date    Varchar2(10);  v_isDate   Boolean;  v_isNumber  Boolean;  v_isNumber_17 Boolean;  v_checkbit  CHAR (1);  v_checkcode  CHAR (11)    := '10X98765432';  v_areacode  VARCHAR2 (2000) := '11,12,13,14,15,21,22,23,31,32,33,34,35,36,37,41,42,43,44,45,46,50,51,52,53,54,61,62,63,64,65,71,81,82,91,';     --[isNumber]--  Function isNumber (p_string in varchar2) Return Boolean  Is    i      number;    k      number;    flag    boolean;    v_length  number;  Begin    /*    算法:      通过ASCII码判断是否数字，介于[48, 57]之间。      select ascii('0'),ascii('1'),ascii('2'),ascii('3'),ascii('4'),ascii('5'),ascii('6'),ascii('7'),ascii('8'),ascii('9') from dual;    */         flag := True;    select length(p_string) into v_length from dual;         for i in 1..v_length loop      k := ascii(substr(p_string,i,1));      if k < 48 or k > 57 then        flag := False;        Exit;      end if;    end loop;         Return flag;  End isNumber;     --[isDate]--  Function isDate (p_date in varchar2) Return Boolean  Is    v_flag     boolean;    v_year     number;    v_month     number;    v_day      number;    v_isLeapYear  boolean;  Begin    --[初始化]--    v_flag := True;         --[获取信息]--    v_year := to_number(substr(p_date,1,4));    v_month := to_number(substr(p_date,5,2));    v_day  := to_number(substr(p_date,7,2));         --[判断是否为闰年]--    if (mod(v_year,400) = 0) Or (mod(v_year,100) <> 0 And mod(v_year,4) = 0) then      v_isLeapYear := True;    else      v_isLeapYear := False;    end if;         --[判断月份]--    if v_month < 1 Or v_month > 12 then      v_flag := False;      Return v_flag;    end if;         --[判断日期]--    if v_month in (1,3,5,7,8,10,12) and (v_day < 1 or v_day > 31) then      v_flag := False;    end if;    if v_month in (4,6,9,11) and (v_day < 1 or v_day > 30) then      v_flag := False;    end if;    if v_month in (2) then      if (v_isLeapYear) then        --[闰年]--        if (v_day < 1 or v_day > 29) then          v_flag := False;        end if;      else        --[非闰年]--        if (v_day < 1 or v_day > 28) then          v_flag := False;        end if;      end if;    end if;         --[返回结果]--    Return v_flag;  End isDate;Begin  /*  返回值说明:    -1   身份证号码位数不对    -2   身份证号码出生日期超出范围    -3   身份证号码含有非法字符    -4   身份证号码校验码错误    -5   身份证号码地区码非法   身份证号码通过校验  */  --[长度校验]--  if p_idcard is null then   return -1;  end if ;  select lengthb(p_idcard) into v_length from dual;  if v_length not in (15,18) then    return -1;  end if;     --[区位码校验]--  if instrb(v_areacode, substr(p_idcard, 1, 2)||',') = 0 then    return -5;  end if;     --[格式化校验]--  if v_length = 15 then    v_isNumber := isNumber (p_idcard);    if not (v_isNumber) then      return -3;    end if;  elsif v_length = 18 then    v_isNumber  := isNumber (p_idcard);    v_isNumber_17 := isNumber (substr(p_idcard,1,17));    if not ((v_isNumber) or (v_isNumber_17 and upper(substr(p_idcard,18,1)) = 'X')) then      return -3;    end if;  end if;     --[出生日期校验]--  if v_length = 15 then    select '19'||substr(p_idcard,7,6) into v_date from dual;  elsif v_length = 18 then    select substr(p_idcard,7,8) into v_date from dual;  end if;  v_isDate := isDate (v_date);  if not (v_isDate) then    return -2;  end if;     --[校验码校验]--  if v_length = 18 then    v_sum :=        ( TO_NUMBER (SUBSTRB (p_idcard, 1, 1))        + TO_NUMBER (SUBSTRB (p_idcard, 11, 1))        )       * 7      +  ( TO_NUMBER (SUBSTRB (p_idcard, 2, 1))        + TO_NUMBER (SUBSTRB (p_idcard, 12, 1))        )       * 9      +  ( TO_NUMBER (SUBSTRB (p_idcard, 3, 1))        + TO_NUMBER (SUBSTRB (p_idcard, 13, 1))        )       * 10      +  ( TO_NUMBER (SUBSTRB (p_idcard, 4, 1))        + TO_NUMBER (SUBSTRB (p_idcard, 14, 1))        )       * 5      +  ( TO_NUMBER (SUBSTRB (p_idcard, 5, 1))        + TO_NUMBER (SUBSTRB (p_idcard, 15, 1))        )       * 8      +  ( TO_NUMBER (SUBSTRB (p_idcard, 6, 1))        + TO_NUMBER (SUBSTRB (p_idcard, 16, 1))        )       * 4      +  ( TO_NUMBER (SUBSTRB (p_idcard, 7, 1))        + TO_NUMBER (SUBSTRB (p_idcard, 17, 1))        )       * 2      + TO_NUMBER (SUBSTRB (p_idcard, 8, 1)) * 1      + TO_NUMBER (SUBSTRB (p_idcard, 9, 1)) * 6      + TO_NUMBER (SUBSTRB (p_idcard, 10, 1)) * 3;    v_mod := MOD (v_sum, 11);    v_checkbit := SUBSTRB (v_checkcode, v_mod + 1, 1);         if v_checkbit = upper(substrb(p_idcard,18,1)) then      return 1;    else      return -4;    end if;  else    return 1;  end if;End Func_checkIdcard;/Show Err;

总结

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