SQL查询按指定字段排序

city_name是字段名，现在要按("北京","上海","广州")   先后顺序把数据查询统计出来？

不知道你什么数据库, 假如是 Oracle:select     count(city_name),  city_name from     tuan_info   where   source_type  = 1   and  city_name in("北京","上海","广州")   group    by   city_nameORDER BY  INSTR('北京,上海,广州', city_name);如果是 SQL Server 用ORDER BY CHARINDEX(city_name, '北京,上海,广州')

追问

是SQL Server 的，怎么写哦，给个完整点的语句好吗

回答

select     count(city_name),  city_name from     tuan_info   where   source_type  = 1   and  city_name in("北京","上海","广州")   group    by   city_nameORDER BY CHARINDEX(city_name, '北京,上海,广州')前面的SQL都是一样的啊。只是 增加一个  ORDER BY 的排序处理。

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在吗，不行的，提示有错啊，是什么问题哦[SQL] select count(city_name), city_name from tuan_info where source_type  = 1 and  city_name in("北京","上海","广州") group by city_name ORDER BY CHARINDEX(city_name, '北京,上海,广州');[Err] 1305 - FUNCTION data_group.CHARINDEX does not exist

回答

你这个是什么数据库啊？CHARINDEX  是 SQL Server 自带的函数啊。

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那个，，是MYSQL的哦，怎办

回答

MySQL  就换一个函数   INSTRselect     count(city_name),  city_name from     tuan_info   where   source_type  = 1   and  city_name in("北京","上海","广州")   group    by   city_nameORDER BY INSTR( '北京,上海,广州',   city_name)